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Maths problem on Percentages

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Maths problem on Percentages

Headisocto

Member
Sep 29, 2019
9
0
So guys, for some reasons, I've forgotten how to work with percentages.

For example, if 1586 is 91% of X (unknown number), and I'm trying to find X. First of all, that means that 1586 is 9% less than the number I'm tryna find, right?

Now does that mean there are two methods to go about working this maths problem?

method 1:

do 1586/91 x 100 to find the X


method 2:

do 1586 x 1.09 to find x.


are these methods correct?
 

Ezekiel

Active member
Editor
Sep 9, 2019
32
12
First method is correct, but the second one is NOT correct

Let's imagine it was not 91%, but 50%. If you applied the second method, rather than dividing by 0.5 (which would double it) you'd be multiplying by 1.5, which is clearly not the same as doubling.
 

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